2. Measured along the surface of the water, a rectangular swimmingpool has a len

Question

2. Measured along the surface of the water, a rectangular swimmingpool has a length of 15 m. Along this length, the flat bottom ofthe pool slopes down at an angle of 11 degrees below thehorizontal, from one end to the other. By how much does thepressure at the bottom of the deep end exceed the pressure at thebottom of the shallow end?
a. 2.9 × 10^4 Pa
b. 6.1 × 10^4 Pa
c. 1.5 × 10^5 Pa
d. 4.3 × 10^4 Pa
e. 9.7 × 10^4 Pa

Thanks! Will ratelifesaver for best answer ANDexplanation.
a. 2.9 × 10^4 Pa
b. 6.1 × 10^4 Pa
c. 1.5 × 10^5 Pa
d. 4.3 × 10^4 Pa
e. 9.7 × 10^4 Pa

Thanks! Will ratelifesaver for best answer ANDexplanation.

Explanation / Answer

The hydrostatic pressure at depth below Liquid surface isgiven by:
p = p0 + ·g·h

So the pressure difference between two different depths is:
?p = ·g·?h

?h can be found from the angel. The tangent of the angle of a slopeequals ratio of height difference to horizontal distance. So
tan(11°) = ?h / 15m
=>
?h = 15m · tan(11°) = 2.916m

Hence:
?p = 1000kg/m³ · 9.81m/s² · 2.916m
= 28606 Pa
= 0.282atm A: (a) Hope this helps~Please Rate! A: (a) Hope this helps~Please Rate!

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