A thin film of cryolite( nc = 1.27) is applied to a camera lens ( ng = 1.61 ). T

Question

A thin film of cryolite( nc = 1.27) is applied to a camera lens ( ng = 1.61 ). The coating is designedto reflect wavelengths at the blue end of the spectrum and transmitwavelengths in the near infrared. What minimum thickness gives highreflectivity at 458 nm?
Answer in units of nm. Whatminimum thickness gives high transmission at 916 nm?
Answer in units of nm. A thin film of cryolite( nc = 1.27) is applied to a camera lens ( ng = 1.61 ). The coating is designedto reflect wavelengths at the blue end of the spectrum and transmitwavelengths in the near infrared. What minimum thickness gives highreflectivity at 458 nm?
Answer in units of nm. Whatminimum thickness gives high transmission at 916 nm?
Answer in units of nm. Whatminimum thickness gives high transmission at 916 nm?
Answer in units of nm.

Explanation / Answer

We know that              n = (ng - nc) * t The thickness of the thin film is             t = n /(ng - nc)    for n = 1 we have             t = 1*458nm / 0.34               = 1347nm    For = 916 nm             t = 1*916nm / 0.34               = 2694 nm    For = 916 nm             t = 1*916nm / 0.34               = 2694 nm               = 2694 nm

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