A. A 6500 kg bus goes around a turn (radius =265m) at aconstant speed of 25.0 m/

Question

A. A 6500 kg bus goes around a turn (radius =265m) at aconstant speed of 25.0 m/s. What centripetal acceleration ispresent to keep the bus on the road? B. What total centripetal force is needed to make the bus turnso that it will stay on the road? C. What is the minimum coefficient of static friction (thetires roll if does not slide so it is actually at rest with respectto the road if the do not being to slip) between the bus tires andthe road that will allow the bus to make the turn? D. Is this a safe speed for the bus to be traveling giventhat: Coefficient of friction for tires on dry road is 0.900 andcoefficient for friction for tires on snow is 0.150. A. A 6500 kg bus goes around a turn (radius =265m) at aconstant speed of 25.0 m/s. What centripetal acceleration ispresent to keep the bus on the road? B. What total centripetal force is needed to make the bus turnso that it will stay on the road? C. What is the minimum coefficient of static friction (thetires roll if does not slide so it is actually at rest with respectto the road if the do not being to slip) between the bus tires andthe road that will allow the bus to make the turn? D. Is this a safe speed for the bus to be traveling giventhat: Coefficient of friction for tires on dry road is 0.900 andcoefficient for friction for tires on snow is 0.150.

Explanation / Answer

answer: a = v2/r = 252/265m/s2 >> compute this B. What total centripetal force is needed to make the bus turnso that it will stay on the road? answer: force = ma = (6500 a) N >>> computethis C. What is the minimum coefficient of static friction (thetires roll if does not slide so it is actually at rest with respectto the road if the do not being to slip) between the bus tires andthe road that will allow the bus to make the turn? answer: The centripetal force is provided by friction.so force = ma = (Normal force) = mg = a/g >>> compute this. D. Is this a safe speed for the bus to be traveling giventhat: Coefficient of friction for tires on dry road is 0.900 andcoefficient for friction for tires on snow is 0.150. answer: compare computed in part (c) with .9 and.15.

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