A. -270.2 -92.31 C. 93.31 270.2 3 1 Calculate the free energy change ?G, in kJ,

Question

A. -270.2 -92.31 C. 93.31 270.2 3 1 Calculate the free energy change ?G, in kJ, for the following reaction at 298 K: 60. 0.2 atm 0.2 atm 0.39 atm A. 109 B. 37.32 C. 13.98 D. -37.32 61. The value of Ke, goes down by a factor of 100.0. Compute the value, in kJ, of the change in AGP for the reaction. A. 1.37 B. 11.41 C. 0.382 D. -11.41 ?fthe free energy is equal to10 Okl and it is four times as big as the standard free energy, wh at must thevalue of Q be under standard conditions? A. 20.6 62 B. 0.003 C. 3.25 D. 1.00 63.Calculate the standard free energy of a specific reaction if the formation constant is 1.47 x 10 A. -54.0 kJ B. 23.5 kJ C. 54.0 k D. 2.51 k Which one of the following processes is the fastest? A. AG-23.5 kJ B. ?G= 58.5 kJ C. AG -5800 kJ D. Speed of reaction is unrelated to its free energy change. 64.

Explanation / Answer

at standard condion
T = 298 k
given,
(delta G) = 10.0 KJ
= 10000 J
so,
(delta G0) = 10000/4
= 2500 J

use,
(delta G) = (delta G0) - R*T*lnQ
10000 - 2500 - 8.314*298*lnQ
7500 = 2477.6*lnQ
lnQ = 3.03
Q = 20.6

Answer : option A

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.