What is the kinetic energy of each electron in a beam ofelectrons if the beam pr

Question

What is the kinetic energy of each electron in a beam ofelectrons if the beam produces a diffraction pattern of a crystalwhich is similar to that of a beam of 1.00 eV neutrons?Note: The electron mass is 9.11 ×10–31 kg; and the neutron mass is 1.67× 10–27 kg.

a. 1830 eV
b. 42.8 eV
d. 2.34 ×10–2 eV
e. 3.35 × 106 eV What is the kinetic energy of each electron in a beam ofelectrons if the beam produces a diffraction pattern of a crystalwhich is similar to that of a beam of 1.00 eV neutrons?Note: The electron mass is 9.11 ×10–31 kg; and the neutron mass is 1.67× 10–27 kg. 1830 eV 42.8 eV 2.34 ×10–2 eV 3.35 × 106 eV

Explanation / Answer

The de-broglie wavelength of the neutrons is givenby                 = h/(2meV) Here h =6.626*10-34Js           m =1.67× 10–27 kg           eV =(1.6*10-19)(1.00)J    So. = 2.8662e-11 m The kinetic energy of the electron is            E = h2/(2m)                Here m =9.11*10-31kg So ,E = 1830 eV            The kinetic energy of the electron is            E = h2/(2m)                Here m =9.11*10-31kg So ,E = 1830 eV                    

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