A solid cylinder has amass of 2.0kg and radius 2.5cm. The cylinder starts from r

Question

A solid cylinder has amass of 2.0kg and radius 2.5cm. The cylinder starts from rest on aninclined plane, 30cm vertically above the horizontal surface of atable. What is the linear velocity of the cylinder when itjust reaches the bottom of the inclined plane? The moment ofinertia of the cylinder is I=(1/2)mR^2
I know that KEf=1/2 mvf2 +1/2 Iw2 and your equation that you need to manipulate ismgh=1/2 mvf2 + 1/2 Iw2 A solid cylinder has amass of 2.0kg and radius 2.5cm. The cylinder starts from rest on aninclined plane, 30cm vertically above the horizontal surface of atable. What is the linear velocity of the cylinder when itjust reaches the bottom of the inclined plane? The moment ofinertia of the cylinder is I=(1/2)mR^2
I know that KEf=1/2 mvf2 +1/2 Iw2 and your equation that you need to manipulate ismgh=1/2 mvf2 + 1/2 Iw2

Explanation / Answer

Ok you have everything here that you need only you need to rememberthe equation w= rv Thus, the new equation becomes mgh=1/2 mvf2 +1/2 I(rv)2 From here plug in all of your values in SI units m= 2.0kg g=9.80 m/s^2 h= 30cm/100= .30 m Vf= solving for it I=(1/2)mR^2 = .5*2.0kg*(2.5/100)= 6.25e-4 r= 2.5cm/100= .025m Thus,    2.0kg*9.8*.30m= .5*2.0kg*Vf^2+ .5*(6.25e-4) (.025)^2 * Vf^2 You can now isolate the term Vf and solve in a calculator for theanswer Good luck!

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