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A 9.5-kg monkey is hanging by one arm from a branch and is swingingon a vertical

ID: 1754670 • Letter: A

Question

A 9.5-kg monkey is hanging by one arm from a branch and is swingingon a vertical circle. As an approximation, assume a radial distanceof 65 cm between the branch and the pointwhere the monkey's mass is located. As the monkey swings throughthe lowest point on the circle, it has a speed of 2.8 m/s. (a) Find the magnitude of the centripetal forceacting on the monkey.
1 N

(b) Find the magnitude of the tension in the monkey's arm.
2 N
(a) Find the magnitude of the centripetal forceacting on the monkey.
1 N

(b) Find the magnitude of the tension in the monkey's arm.
2 N

Explanation / Answer

Centripetal force = mv2/r m= mass=9.5 kg v= velocity = 2.8 m/s r = distance from axis = 0.65 m Putting the values , Centripetal force = 9.5 * 2.82/0.65 = 118.2 N b )Tension in his hand balances the weight as well as provide therequired centripetal force . So tension = weight +centripetal acceleration = 118 + 9.5*9*.8 =211.3 N

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