Joe pushes down the length of the nadle of a 13.5 kg lawnspreader. The handle ma

Question

Joe pushes down the length of the nadle of a 13.5 kg lawnspreader. The handle makes an angle of 46.5 degrees with thehorizontal. Joe wishes to accelerate the spreader from restto 1.32 m/s in 1.3 s. What force must Joe apply to the handle? Answer in units of N. Joe pushes down the length of the nadle of a 13.5 kg lawnspreader. The handle makes an angle of 46.5 degrees with thehorizontal. Joe wishes to accelerate the spreader from restto 1.32 m/s in 1.3 s. What force must Joe apply to the handle? Answer in units of N.

Explanation / Answer

mass m = 13.5 kg angle = 46.5 degrees Initial velocity u = 0 m/ s time t= 1.3 s final velocity v = 1.32 m / s Accleration a = ( v - u ) / t                     = 1.0153 m / s ^ 2 we know   accleration a = Applied force /masss from this applied force F cos = m a                                            F = ma / cos                                               = 19.91 N

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