Fill in the blank. Round your answer to three significant figures. V Solution If

Question

Fill in the blank.

Round your answer to three significant figures.

V

Explanation / Answer

If each capacitor carries a maximum 19.0 V, You have to calculate the total voltage drop across theconnection for which no individual drop exceeds 19.0 V. Cnet = total capacitance :    1/Cnet = 1/(25+25) + 1/19 + 1/(25+25)    => Cnet = 1900/176 F = 10.795 F    Also, if some voltage is applied across theconnection, total charge would be equally distributed across thethree series entities, all having the same charging current.    Maximum voltage drop would be (Q/C)max.    Since Q is same for all,    C should be minimum for Vmax.    This would give us the safest case when no capacitorbreaks down.    The C value of the 19 F capacitor is least, theothers being (25 +25=)50 F each.    So, Q = CV = 19*19C = 361 C    So, Vnet = Q/C1 + Q/C2 + Q/C3 = Q*1/Cnet = 361/10.795 V = 33.44 V ~ 33.4 V

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