2. Q.28-2 Anelectric field of 1.7 KV/m and a magnetic field of 0.422 T act on am

Question

2. Q.28-2

Anelectric field of 1.7 KV/m and a magnetic field of 0.422 T act on amoving electron to produce no net force. If the fields areperpendicular to each other, what is the electron speed? Give theanswer in km/s and to three significant figures.

2. Q.28-2

Anelectric field of 1.7 KV/m and a magnetic field of 0.422 T act on amoving electron to produce no net force. If the fields areperpendicular to each other, what is the electron speed? Give theanswer in km/s and to three significant figures.

Explanation / Answer

Given :             Electric field ( E) = 1.7 kV /m    = 1.7 x 103   V /m             Magnetic field ( B) = 0.422 T Lorentz Force is :                 F = B q v   +   E q The electron is moving such that the net force F = 0             0   =   B qv   +   E q or      B q v   = - E q or         v       =    - E /B                      =   -(1.7 x 103   V/m) / 0.422 T                      = - 4.028 x 103   m /s Here -ve sign represents the direction . Hence velocity of electron is :   v   = 4.028 x 103   m /s Hope this helps u!

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