23(3). A certain skydiver free falls until she reaches aspeed of 70 ft / sec. Sh

Question

23(3). A certain skydiver free falls until she reaches aspeed of 70 ft / sec. She then opens her parachute andexperiences an initial upwards acceleration of 30 ft / sec2. What will be her terminal speed ( thespeed with which she will fall with no acceleration ) if theretarding force of her parachute is proportional to her speed ofdescent ? 23(3). A certain skydiver free falls until she reaches aspeed of 70 ft / sec. She then opens her parachute andexperiences an initial upwards acceleration of 30 ft / sec2. What will be her terminal speed ( thespeed with which she will fall with no acceleration ) if theretarding force of her parachute is proportional to her speed ofdescent ?

Explanation / Answer

when she opens the parachute, the net force on her is upwards: net force = ma retarding force - weight = k(70) - mg = ma = m(30) k = m( g + 30) /70 At terminal speed, retarding force exactly matches weight: k (terminal velocity) = mg terminal velocity = mg/k Substitute for k from the previous equation. Hope this helps!

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