Learning Goal: To understand projectile motion by considering horizontal constan

Question

Learning Goal: To understand projectile motion by considering horizontal constant velocity motion and vertical constant acceleration motion independently. Projectile motion refers to the motion of unpowered objects (called projectiles) such as balls or stones moving near the surface of the earth under the influence of the earth's gravity alone. In this analysis The range R of the ball refers to how far it moves horizontally, from just after it is launched until just before it lands. Range is defined as x2 - x0, or just x2 in this particular situation since x0 = 0. Range can be calculated as the product of the flight time t2 and the x component of the velocity vx (which is the same at all times, so vx = v0,x). The value of vx can be found from the launch speed v0 and the launch angle theta using trigonometric functions, as was done in Part B. The flight time is related to the initial y component of the velocity, which may also be found from v0, and theta using trig functions. The following equations may be useful in solving projectile motion problems, but these equations apply only to a projectile launched over level ground from position (xo = yo = 0) at time to = 0 with initial speed v0 and launch angle theta measured from the horizontal. As was the case above, t2 refers to the flight time and R refers to the range of the projectile. flight time: t2 = 2v0,y / g = 2v0 sin( theta ) / g range: R = vxt2 = v02 sin (2 theta)/g In general, a high launch angle yields a long flight time but a small horizontal speed and hence little range. A low launch angle gives a larger horizontal speed; but less flight time in which to accumulate range. The launch angle that achieves the maximum range for projectile motion over level ground is 45 degrees.

Explanation / Answer

Increase v0 above 30 m/s and Reduce from 60 degrees to 45 degrees the rest are all false

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