A billiard ball is moving in the x-direction at 4.0 m/s andstrikes another billi

Question

A billiard ball is moving in the x-direction at 4.0 m/s andstrikes another billiard ball moving in the y direction at 1.5 m/s.After the collision, the second ball stops. Two balls haveidentical mass. What is the speed of the first ball after collision and whatis the direction of the first ball relative to positivex-axis? A billiard ball is moving in the x-direction at 4.0 m/s andstrikes another billiard ball moving in the y direction at 1.5 m/s.After the collision, the second ball stops. Two balls haveidentical mass. What is the speed of the first ball after collision and whatis the direction of the first ball relative to positivex-axis?

Explanation / Answer

I have to make a few assumtions for my answer.
1 We are neglecting friction. 2 The collision is perfect, meaning no energy is lost. When the 2 balls collide, the 2nd ball transfers its completeenergy to the 1st ball. Energy is related by .5mv2.Since we are dealing with equal masses, we can ignore .5m, leavingonly v2. the new speed can be found by(42(2)+1.52(2))=4.02 m/s. I took the vx2 (enery in x) +vy2 (energy in y), square rooted them tofind the resulting energy, then square rooted that to find velocity(.5m would be canceled out here if you kept them in) the angle can be found bytan-1(1.52/42)=8o relative to the x axis

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