An RLC circuit has 150 resistance, 5.0Fcapacitance and 600mH inductance conected

Question

An RLC circuit has 150 resistance, 5.0Fcapacitance and 600mH inductance conected to an AC source with avoltage V= (140V)sin(1000t), t is in seconds. Calculate: a. impedance of the circuit b. Irms that flows through the circuit c. the disipated power d. phase of the angle between the voltage and thecurrent e. frequency of resonance of the circuit I did it but, the numbers are too high, there has to be a lotof mistakes. I have a couple more problems if anyone is interestedi can pay. An RLC circuit has 150 resistance, 5.0Fcapacitance and 600mH inductance conected to an AC source with avoltage V= (140V)sin(1000t), t is in seconds. Calculate: a. impedance of the circuit b. Irms that flows through the circuit c. the disipated power d. phase of the angle between the voltage and thecurrent e. frequency of resonance of the circuit I did it but, the numbers are too high, there has to be a lotof mistakes. I have a couple more problems if anyone is interestedi can pay.

Explanation / Answer

. 1.   = 2**f = 1000 2.   f = (1000)/(2*) = 159.2 Hertz 3.   XL = *L = (1000)*(600.0E-3Henry) = 600.0 4.   XC = 1/(*C) = 1/[(1000)*(5.0E-6 Farad) = 200.0 5.   Z = impedance = {(R)2 +(XL - XC)2}(1/2) ={(150)2 + (600 -200)2}(1/2) = 427.2 6.   Vrms = (140Volts_peak)*(1/(2)) = 99.0 volts_rms 7.   Irms = (Vrms)/(Z) = (99volts_rms)/(427.2) = 231.8E-3 Ampere_rms 8.   Power =(Vrms)*(Irms)*cos() = (99.0volts_rms)*(231.8E-3 Ampere_rms)*(150/427.2) =8.055 Watts 9.   = arctan[(XL -XC)/R] = 69.44degrees . 10.   r = [L*C](-1/2) =577.35 radians/second 11.   fr = (r)/(2*)= 91.9 Hertz .

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