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The first question I looked at regarding this problem was notfor this book it ap

ID: 1748326 • Letter: T

Question

The first question I looked at regarding this problem was notfor this book it appears. Question 75 for Ch 18 in College Physics 6 ED WilsonBuffa Lou, reads A 3.0 Mohm resistor is connected in series with a.28microFarrad capacitor. This arrangement is then connectedacross four 1.5V batteries (also in series). (a) What is themaximum current in the circuit and when does it occur? (b)What precentage of teh maximum current is in the circuit after4.0s? (c) What is the maximum charge on the capacitor andwhen does it occur? (d) What precentage of the maximum charge is onthe capacitor after 4.0s? The answers according to the back of the book (a) 2.0*10^-3A at t=0 (b).080% (c)1.7*10^-6C at a very long time after connection (d)99.9% I come up with 2.0*10^-6 for (a) can some one help meunder stand why? The first question I looked at regarding this problem was notfor this book it appears. Question 75 for Ch 18 in College Physics 6 ED WilsonBuffa Lou, reads A 3.0 Mohm resistor is connected in series with a.28microFarrad capacitor. This arrangement is then connectedacross four 1.5V batteries (also in series). (a) What is themaximum current in the circuit and when does it occur? (b)What precentage of teh maximum current is in the circuit after4.0s? (c) What is the maximum charge on the capacitor andwhen does it occur? (d) What precentage of the maximum charge is onthe capacitor after 4.0s? The answers according to the back of the book (a) 2.0*10^-3A at t=0 (b).080% (c)1.7*10^-6C at a very long time after connection (d)99.9% I come up with 2.0*10^-6 for (a) can some one help meunder stand why?

Explanation / Answer

Given : Initial current in the circuit   i = total emf / resistance                                                  = 4 ( 1.5 V ) / 3 M                                                  = 2* 10 -6 A       I hope there is a typingmistake in the text book    I hope it helps you                                                  = 4 ( 1.5 V ) / 3 M                                                  = 2* 10 -6 A       I hope there is a typingmistake in the text book    I hope it helps you
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