A trailer with loaded weight F rightarrow g is being pulled by a vehicle with a

Question

A trailer with loaded weight F rightarrow g is being pulled by a vehicle with a force P rightarrow as shown. The trailer is loaded such that its center of mass is located as shown. Ignore the force of rolling friction and let a represent the x-component of acceleration of the trailer. Find the vertical component of P rightarrow in terms of the given parameters. Assume a = 2.00 m/s2 and h =1.50 m. What must be the value of d so that Py =0 (i.e. no vertical load on the vehicle)? Find the values of Px and Py given that Fg = 1500 N,d= 0.800 m,L = 3.00 m, h = 1.50 m and a = -2.00 m/s2.

Explanation / Answer

(a)the vertical component of P is P1= P * sin Here,P is the applied force and is the angle at whichthe force is applied (b)the value of d so that Py= 0 is Fg= m * a * sin or mg = m * a * sin or g = a * sin = a * (d/h) or d = (h/a) * g g = 9.8 m/s^2 (c)the values of Px and Py Px= Fg* sin = mg * sin = mg* (d/(d^2 + h^2)^(1/2)) or Px= m * g * (d/(d^2 + h^2)^(1/2)) Py= Fg* cos = mg * cos = mg* (h/(d^2 + h^2)^(1/2))

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