PLEASEE HELP A solid circular disk has a mass of 4.59 kg and a radius of 0.389m.
ID: 1748211 • Letter: P
Question
PLEASEE HELPA solid circular disk has a mass of 4.59 kg and a radius of 0.389m. Each of three identical thin rods has a mass of 0.757 kg. Therods are attached perpendicularly to the plane of the disk at itsouter edge to form a three-legged stool (see the figure). Find themoment of inertia of the stool with respect to an axis that isperpendicular to the plane of the disk at itscenter. (Hint: When considering the moment of inertia ofeach rod, note that all of the mass of each rod is located at thesame perpendicular distance from the axis.) PLEASEE HELP
Explanation / Answer
the moment of inertia of the stool will be the sum ofmoment of inertia of circuilar disk and the moment of inertia of the three cylindricallegs the moment of inertia of the circuilar disk willbe Idisk = (1/2) m r2 the moment of inertia of the cylindrical leg willbe Ileg = m r2 so the the moment of inertia of the stool willbe Istool = Idisk + 3(Ileg) = ........... kg.m2 hope you got it hope you got it
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