A 74 kg window cleaner uses a 14 kg ladder that is 5.3 mlong. He places one end

Question

A 74 kg window cleaner uses a 14 kg ladder that is 5.3 mlong. He places one end on the ground 2.0m from a wall, rests the upper end against a cracked window, andclimbs the ladder. He is 3.4 m up alongthe ladder when the window breaks. Neglect friction between theladder and window and assume that the base of the ladder does notslip. (a) When the window is on the verge ofbreaking, what is the magnitude of the force on the window from theladder?
1
(b) When the window is on the verge of breaking, what is themagnitude of the force on the ladder from the ground?
2
(c) What is the angle of this force on the ladder?
3 (a) When the window is on the verge ofbreaking, what is the magnitude of the force on the window from theladder?
1
(b) When the window is on the verge of breaking, what is themagnitude of the force on the ladder from the ground?
2
(c) What is the angle of this force on the ladder?
3

Explanation / Answer

Draw Force Digram. Draw distances from floor up ladder and of floor toladder. This problem has a look of torque problem. Put axis of rotation ina place which cancels out unknowns and you should be able to solve.This should be on the floor where the ladder meets. Watch forpositive and negative signs. CCW=+ CW-

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