An ideal polarizer passes 50% of the incident light intensitywhen the incident l
ID: 1747919 • Letter: A
Question
An ideal polarizer passes 50% of the incident light intensitywhen the incident light is unpolaried. Unpolaried light froma particular lamp has an intensity measured with a lightmeter. a.) What is the intensity reading on the meter when a singleideal polarizer is inserted in the beam? b.) What is the intensity reading if the second idealpolarizer is inserted in the beam with its polarization directionaligned parallel to that of the first polrizer? c.) What is the intensity reading when the second polarizer isrotated by 45 degrees? d.) What is the intensity reading when the second polarizer isrotated by 90 degrees? An ideal polarizer passes 50% of the incident light intensitywhen the incident light is unpolaried. Unpolaried light froma particular lamp has an intensity measured with a lightmeter. a.) What is the intensity reading on the meter when a singleideal polarizer is inserted in the beam? b.) What is the intensity reading if the second idealpolarizer is inserted in the beam with its polarization directionaligned parallel to that of the first polrizer? c.) What is the intensity reading when the second polarizer isrotated by 45 degrees? d.) What is the intensity reading when the second polarizer isrotated by 90 degrees?Explanation / Answer
(a). the intensity reading on the meter when a single idealpolarizer is inserted in the beam = 50 % of unpolarised = I / 2 where I = intensity of unpolarised light (b). the intensity reading if the second ideal polarizer isinserted in the beam with its polarization direction alignedparallel to that of the first polrizer I ' = I / 2 = 0.5 I (c). the intensity reading when the second polarizer isrotated by 45 degrees is I " = ( I / 2 ) cos 245 = 0.25 I (d). the intensity reading when the second polarizer isrotated by 90 degrees = 0Related Questions
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