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Two trains are traveling toward each other at 30.5 m/s relative to the ground. O

ID: 1747843 • Letter: T

Question

Two trains are traveling toward each other at 30.5 m/s relative to the ground. One train is blowinga whistle at 1060 Hz. (a) What frequency will be heard on the othertrain in still air?
1 Hz

(b) What frequency will be heard on the other train if the wind isblowing at 30.5 m/s toward the whistle andaway from the listener?
2 Hz

(c) What frequency will be heard if the wind direction isreversed?
3 Hz

Section 17-9 The Doppler Effect (a) What frequency will be heard on the othertrain in still air?
1 Hz

(b) What frequency will be heard on the other train if the wind isblowing at 30.5 m/s toward the whistle andaway from the listener?
2 Hz

(c) What frequency will be heard if the wind direction isreversed?
3 Hz
Section 17-9 The Doppler Effect

Explanation / Answer

Given frequency f = 1060Hz v = 343 m/s Two trains are traveling toward each other at 30.5 m/s relative to the ground a) the frequency heard in still air is     f ' =f(v+vD/v-vS)          =(1060Hz)(343+30.5/343-30.5)          =---------Hz b) In a frame of reference where the air seems still , thevelocity of the detector is vD = 30.5 -30.5 = 0, andthat of the source is vS = 2(30.5) therefore     f ' = f(v+vD/v-vS)          =(1060Hz){343+0/343-2(30.5)}           =---------Hz c) we again pick a frame of reference where the airseems still . Now , the velocity of the source is vS =30.5-30.5=0, and that of the detector is vD = 2(30.5) therefore    f ' = f(v+vD/v-vS)          =(1060Hz){343+2(30.5)/343-0}          =---------Hz          =(1060Hz){343+0/343-2(30.5)}           =---------Hz c) we again pick a frame of reference where the airseems still . Now , the velocity of the source is vS =30.5-30.5=0, and that of the detector is vD = 2(30.5) therefore    f ' = f(v+vD/v-vS)          =(1060Hz){343+2(30.5)/343-0}          =---------Hz          =(1060Hz){343+2(30.5)/343-0}          =---------Hz