A block of mass = 0.20 kg is attached to teh end of ahorizontal spring of force

Question

A block of mass = 0.20 kg is attached to teh end of ahorizontal spring of force constant k= 10N/m and rests on a smoothhorizontal surgace. The block is set in motion by pulling it 5 cmto the left and then releasing it from rest at time t=0. Determine: a. The period of the subsequent oscillations b. max speed and max acc of the block c. total mechanical energy of the system d. expression relating the position of the block to time.Assign numerical values to any constants which you employ. e. total distance through which the block moves from t= 0 tot= 2.0 sec I am stuck at part b of the question and don't know how to dothe rest of the parts A block of mass = 0.20 kg is attached to teh end of ahorizontal spring of force constant k= 10N/m and rests on a smoothhorizontal surgace. The block is set in motion by pulling it 5 cmto the left and then releasing it from rest at time t=0. Determine: a. The period of the subsequent oscillations b. max speed and max acc of the block c. total mechanical energy of the system d. expression relating the position of the block to time.Assign numerical values to any constants which you employ. e. total distance through which the block moves from t= 0 tot= 2.0 sec I am stuck at part b of the question and don't know how to dothe rest of the parts

Explanation / Answer

initial energy = 0.5kx^2 -> formula for elastic potentialenergy since energy is conserved, all the initial energy will betransferred to the kinetic energy, as when you let go, blobk hasonly kinetic energy hence kinetic energy = 0.5mv^2 -> formula for kinetic energy since initial energy = final energy 0.5kx^2 = 0.5mv^2 divide 0.5 both sides kx^2 = mv^2

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