A ball having a mass of 170 g strikes a wall a speed of5.0 m/s and rebounds with

Question

A ball having a mass of 170 g strikes a wall a speed of5.0 m/s and rebounds with only 50% of its initial kinetic energy.If the ball was in contact with the wall for 7.8 ms, what was themagnitude of the average force exerted by the wall on the ballduring this time interval? A ball having a mass of 170 g strikes a wall a speed of5.0 m/s and rebounds with only 50% of its initial kinetic energy.If the ball was in contact with the wall for 7.8 ms, what was themagnitude of the average force exerted by the wall on the ballduring this time interval?

Explanation / Answer

mass m = 170 g =0.17 kg initial speed u = 5 m / s final K.E = 50 % of initial K.E ( 1/ 2) m v ^ 2 = ( 50 / 100 ) ( 1/ 2) m u ^ 2               v = u 0.5                  = 3.535 m / s So, change in velocity dv = v - u                                       = -8.5355 m / s      Since   v = -ve because it moves opposite toinitial direction So, force F = m dv / t where t = 7.8 ms = 7.8 * 10 ^ -3 s So, F = 186 N

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