A rubber ball (mass 0.29 kg) isdropped from a height of 1.1 m ontothe floor. Jus

Question

A rubber ball (mass 0.29 kg) isdropped from a height of 1.1 m ontothe floor. Just after bouncing from the floor, the ball has a speedof 3.9 m/s. (a) What is the magnitude and direction of theimpulse imparted by the floor to the ball? Magnitude 1 kg· m/s Direction 2---Select---radially inwardclockwiseradially outwarddownwardupward
(b) If the average force of the floor on the ball is 15 N, how long is the ball in contact with thefloor?
3 s (a) What is the magnitude and direction of theimpulse imparted by the floor to the ball? Magnitude 1 kg· m/s Direction 2---Select---radially inwardclockwiseradially outwarddownwardupward
(b) If the average force of the floor on the ball is 15 N, how long is the ball in contact with thefloor?
3 s Magnitude 1 kg· m/s Direction 2---Select---radially inwardclockwiseradially outwarddownwardupward

Explanation / Answer

              Mass (m) = 0.29 kg               Initial velocity (v1) = 2gh                                              = 2*9.8*1.1   = 4.64 m /s               final velocity (v2) = 3.9 m /s (a)      we know that ,             Impulse   J = m (v2 - v1)                               = 0.29 ( 3.9 - 4.64)                               = - 0.215 kg . m /s Direction is upwards. (b)         we knowthat                           F.t = J                        t = J / F                                 = 0.215 / 15 = 0.0143 s Hope this helps u!

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