A ball and bat,approach one another each with the same speed of 2.30 m/s,collide
ID: 1744216 • Letter: A
Question
A ball and bat,approach one another each with the same speed of 2.30 m/s,collide.Find the speed of the ball after the collision. (Assume the mass ofthe bat is much much larger than the mass of the ball and that thisis an elastic collision with no rotational motion).
HINT:Imagine yourself on the massive bat, watching the ballcome toward you. You would see the ball approach the bat at a speedof 2v and bounce off at that same speed with respect to the bat(and you). Since the bat is really moving at a speed, v, what nowis the speed of the ball with respect to the ground?
Explanation / Answer
V1=[m1-m2/m1+m2]U1+[2m2/m1+m2]U2 V2=[m2-m1/m1+m2]U2+[2m1/m1+m2]U1 speed of the ball is v2 m1 is greater than m2 so we can neglect m2 v2=-u2+2u1=u1=2.30m/sec
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