In baseball the rules specify that the ball is 22.5cm incircumference with a mas

Question

In baseball the rules specify that the ball is 22.5cm incircumference with a mass of 150kg. If a pitcher throws a fastballat 33.0 m/s, it's spin typically can be 22.0 rev/s. We canreasonably model the ball as a uniform solid sphere.
Part A: How much total kinetic energy has the pitcher given thisball? I understand KE=1/2mv2 + 1/2 (2/5 mr2)w2 My answer comes up to be 153.265, but it's wrong. Don't know what I'm doing wrong.
Part A: How much total kinetic energy has the pitcher given thisball? I understand KE=1/2mv2 + 1/2 (2/5 mr2)w2 My answer comes up to be 153.265, but it's wrong. Don't know what I'm doing wrong.

Explanation / Answer

        Given that thecircumference is 2r = 22.5cm = 0.225 m       then radius is r =0.225m /2         mass is m = 150kg         velocity is v =33.0 m/s         The angularvelocity is = 22.0 rev/s = 22.0 *2 rad/s   ----------------------------------------------------------------           totalkinetic energy is K = (1/2)mV2 +(1/2)I2                                              = (1/2)mV2 +(1/2)(2/5)(mr2)2                                                 = 82410 J    

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