A satellite moves in a circular orbit around Earth at a speedof 4227 m/s. (a) De

Question

A satellite moves in a circular orbit around Earth at a speedof 4227 m/s. (a) Determine the satellite's altitude above the surface ofEarth.
m

(b) Determine the period of the satellite's orbit.
h (a) Determine the satellite's altitude above the surface ofEarth.
m

(b) Determine the period of the satellite's orbit.
h

Explanation / Answer

part A>>>>       mv2 / (R+h) = G m Me /(R+h)2   where R is radius of earth, and Me is mass of earth. the m's cancel out. 6.37E6 + h = (6.67E-11)(5.98E24) /(4227)2    solve for h toget:    h = 1.595E7 m. part B>>>>    T = 2 (R+h) /v =   33,183 sec = 9.22 hours.

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