a projectile is thrown with velocity \"v\" at an angle \"\"with horizontal. when

Question

a projectile is thrown with velocity "v" at an angle ""with horizontal. when the projectile is at a height equal to halfof the maximum height , the vertical component of velocity ofprojectile is     1.   v sin X 3     2.   v sin/3     3.   v sin/2     4.   v sin/3 a projectile is thrown with velocity "v" at an angle ""with horizontal. when the projectile is at a height equal to halfof the maximum height , the vertical component of velocity ofprojectile is     1.   v sin X 3     2.   v sin/3     3.   v sin/2     4.   v sin/3

Explanation / Answer

Hmax=u2sin2/2g H=v2sin2/2g v2-u2=2*-g*h v2-(vsin)2=2*-g*H/2 v2=(vsin)2-v2sin2/2 v=vsin/2 Hence we get by it.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.