An 80.0 kg skydiver jumps out of a balloon at an altitude of1180 m and opens the
ID: 1743035 • Letter: A
Question
An 80.0 kg skydiver jumps out of a balloon at an altitude of1180 m and opens the parachute at analtitude of 185 m. (a) Assuming that the total retarding force on the diver isconstant at 50.0 N with the parachute closed and constant at 3600 Nwith the parachute open, what is the speed of the diver when helands on the ground?(b) Do you think the sky diver will be injured? Explain. (c) At what height should the parachute be opened so that thefinal speed of the skydiver when he hits the ground is 5.00 m/s?
(d) How realistic is the assumption that the total retardingforce is constant? Explain your answer.
An 80.0 kg skydiver jumps out of a balloon at an altitude of1180 m and opens the parachute at analtitude of 185 m. (a) Assuming that the total retarding force on the diver isconstant at 50.0 N with the parachute closed and constant at 3600 Nwith the parachute open, what is the speed of the diver when helands on the ground?
(b) Do you think the sky diver will be injured? Explain. (c) At what height should the parachute be opened so that thefinal speed of the skydiver when he hits the ground is 5.00 m/s?
(d) How realistic is the assumption that the total retardingforce is constant? Explain your answer.
Explanation / Answer
The acceleration a for the height h=1180-185=995m as mg-50=ma 80*9.8-50=80*a a=9.175m/s2 So hefalls with the resultant force F=ma=80*9.175=734N The speed at this point as v2-u2=2as v2-0=2*9.175*995 v=135.123m/s If 360N acts then the resultant acceleration as 734-3600=80*a a=-35.825m/s2 v2-u2=2as v2-135.1232=2*-35.825*185 v=70.731m/s Yes the sky diver will be injured as the speed is toohigh. 52-135.1232=2*-35.825*h h=254.4762754m As the atmosphere varies with height so the force constantas. Hence we get by it.Related Questions
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