A billiard ball rolling across a table at 1.55 m/s makes a head-on elastic colli

Question

A billiard ball rolling across a table at 1.55 m/s makes a head-on elastic collision with anidentical ball. Find the speed of each ball after the collisionwhen each of the following occurs. (a) The second ball is initially at rest. 1st ball Enter an exact number. 1 m/s 2nd ball Enter anumber. 2 m/s (b) The second ball is moving toward the first at a speed of1.10 m/s. 1st ball Enter a number. 3 m/s 2nd ball Enter a number. 4 m/s (c) The second ball is moving away from the first at a speed of0.95 m/s. 1st ball Enter a number. 5 m/s 2nd ball Enter a number. 6 m/s (a) The second ball is initially at rest. 1st ball Enter an exact number. 1 m/s 2nd ball Enter anumber. 2 m/s (b) The second ball is moving toward the first at a speed of1.10 m/s. 1st ball Enter a number. 3 m/s 2nd ball Enter a number. 4 m/s (c) The second ball is moving away from the first at a speed of0.95 m/s. 1st ball Enter a number. 5 m/s 2nd ball Enter a number. 6 m/s Enter an exact number. Enter anumber. Enter a number. Enter a number. Enter a number. Enter a number. 1st ball Enter an exact number. 1 m/s 2nd ball Enter anumber. 2 m/s

Explanation / Answer

(B) momentum:    mb*1.55 m/s -mb1.10 m/s = mbv1 +mbv2    1.55 - 1.10 = v1 +v2 kinda same for:    0.5*mb*(1.55m/s)2 + 0.5*mb*(1.10 m/s)2 =0.5mbv12 +0.5mbv22    (1.55 m/s)2 + (1.10m/s)2 = v12 +v22 again solve:    v2 = 0.45 - v1    3.6125 = v12 + (0.45 -v1)2                =v12 + 0.2025 - 0.9v1 +v12            0 = 2v12 - 0.9v1 - 3.41            0 = 2v12 - 0.9v1 - 3.41 now use the quadratic equation:    v1 = [0.9 ±(0.9)2 - 4(2)(-3.41)] / 2*2       v1 =1.55 or -1.10 solve for v2 solve for v2 ...

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.