A billiard ball rolling across a table at 1.45 m/s makes a head-on elastic colli

Question

A billiard ball rolling across a table at 1.45 m/s makes a head-on elastic collisionwith an identical ball. Find the speed of each ball after thecollision when each of the following occurs. (a) The second ball is initially at rest. 1st ball m/s 2nd ball m/s (b) The second ball is moving toward the first at a speedof 1.10 m/s. 1st ball m/s 2nd ball m/s (c) The second ball is moving away from the first at a speedof 0.95 m/s. 1st ball m/s 2nd ball m/s (a) The second ball is initially at rest. 1st ball m/s 2nd ball m/s (b) The second ball is moving toward the first at a speedof 1.10 m/s. 1st ball m/s 2nd ball m/s (c) The second ball is moving away from the first at a speedof 0.95 m/s. 1st ball m/s 2nd ball m/s 1st ball m/s 2nd ball m/s

Explanation / Answer

IN this type of collision if the velocities of the two balls after collision are v1 and v2 the formulae to find out v1 and v2 are v1=[m1-m2/m1+m2]u1+[2m2/m1+m2]u2 v2=[m2-m1/m1+m2]u2+[2m1/m1+m2]u1 (a) The second ball is initially at rest. u2=0 m1=m2 so v1=0 v2=1.45m/sec 1st ball m/s 2nd ball m/s (b) The second ball is moving toward the first at a speedof 1.10 m/s. v1=-1.10m/sec v2=1,45m/sec 1st ball m/s 2nd ball m/s (c) The second ball is moving away from the first at a speedof 0.95 m/s. v1=0.95m/sec v2=1.45m/sec 1st ball m/s 2nd ball m/s

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