Suppose you operate a 100 W lamp continuously for 1 week whenthe power utility r

Question

Suppose you operate a 100 W lamp continuously for 1 week whenthe power utility rate is 20cents/kWh. Show that this costs$3.36. _________________ I know that a kW=1000W. The lamp can operate for 10 hours to reach 1kw which wouldcost .20cents. 100W lamp * 10 hours = 1000W or 1 kW. $3.36/.2=16.8 16.8 hours @ .20cents per hour Is this how you would figure this? I can't find anythinglike it in the book. Suppose you operate a 100 W lamp continuously for 1 week whenthe power utility rate is 20cents/kWh. Show that this costs$3.36. _________________ I know that a kW=1000W. The lamp can operate for 10 hours to reach 1kw which wouldcost .20cents. 100W lamp * 10 hours = 1000W or 1 kW. $3.36/.2=16.8 16.8 hours @ .20cents per hour Is this how you would figure this? I can't find anythinglike it in the book.

Explanation / Answer

   Total energyconsumed   E   =   Power* time   =   100 * 1 * 7 * 24 *3600   =   6.048 *107   J    1kWh   =   3.6 *106   J    =>   E   =   6.048* 107 / 3.6 *106   =   16.8   kWh    Cost   =   rate *energy consumed   =   0.20 *16.8   =   $ 3.36    

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