A) Determine the minimum weight of block C to keep A from sliding, ifµ s between

Question

A) Determine the minimum weight of blockC to keep A from sliding, ifµs between A and the table is0.20.


B) Block C suddenly is lifted off A. What is theacceleration of block A, if µkbetween A and the table is 0.15? A) Determine the minimum weight of blockC to keep A from sliding, if mu s between A and the table is0.20. B) Block C suddenly is lifted off A. What is theacceleration of block A, if mu k between A and the table is 0.15? In the figure, blocks A and B have weightsof 48 N and 21 N,respectively.

Explanation / Answer

consider the forces pulling the system forward andbackward: .    weight of block B pullsforward             friction on block A pulls backward . Using Newton's secondlaw:          forward force - backward force = total mass* acc . You want acc to be zero,so            forward force = backward force .                                  21 = 0.2 ( total weight of A and C) .                                  105 =   48 + weight of C .    weight ofC = 57 Newtons . Now that block C is removed... .           weightof B   - friction on A   =  total mass * acc .           21    -    0.15 * 48  = (total weight / g) * acc .          13.8 =   (48 + 21) /g       *   acc .          acc =   g * 13.8 / 69 = 9.8 * 13.8 /69   = 1.96m/s2

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