The previous question was \"a 10.2K resistor passes acurrent of 2mA, what is the

Question

The previous question was "a 10.2K resistor passes acurrent of 2mA, what is the voltage across this resistor?" So, Iused V=1*R and got 20.4V. ---------------------------- HERE is my question: What is the current through thisresistor when 9V are dropped across it? The previous question was "a 10.2K resistor passes acurrent of 2mA, what is the voltage across this resistor?" So, Iused V=1*R and got 20.4V. ---------------------------- HERE is my question: What is the current through thisresistor when 9V are dropped across it?

Explanation / Answer

The value of the resistor is R = 10.2 K = 10.2 *103 The resistor passes a current of I = 2 mA = 2 *10-3 A The voltage across this resistor is V = I * R or V = 2 * 10-3 * 10.2 * 103 or V = 20.4 V Let the current through this resistor when 9 V are droppedacross it be I1. Here,V1 = (20.4 - 9) V = 11.4 V Therefore,the current through this resistor is I1= (V1/R) or I1= (11.4/10.2 * 103) or I1= 1.11* 10-3 A or I1= 1.11 mA

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.