The pressure of a gas changes from 120 kPa to 50 kPa. Thevolume changes from 45

Question

The pressure of a gas changes from 120 kPa to 50 kPa. Thevolume changes from 45 L to 40 L. if the initial temp. is 81degrees celsius, what is teh final temp. in degree celsius? also, (why do you need to convert the degree celisius tokelvin first in this problem?). thanks The pressure of a gas changes from 120 kPa to 50 kPa. Thevolume changes from 45 L to 40 L. if the initial temp. is 81degrees celsius, what is teh final temp. in degree celsius? also, (why do you need to convert the degree celisius tokelvin first in this problem?). thanks

Explanation / Answer

It is a necessary step to convert the celsius to kelvin. Thisis a standard procedure to follow when applying all gas laws. Thisis because celsius scale shows zero and negative values whichcannot be substituted in the equation. So Kelvin scale which hasvalues only greater than zero is used. P1 = 120 kPa P2 = 50 kPa V1 = 45 L V2 = 40 L T1 = 81 C = 354 K T2 = ? P1 V1 / T1 = P2 V2 / T2 T2 = 50 kPa * 40 L * 354 K / (120 kPa * 45 L)      = 131.11 K Final temperature = 131.11 - 273 = - 141.8 C

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