Suppose your waffle iron is rated at 1.00kW when connected toa 1.20 x 10^2 V sou

Question

Suppose your waffle iron is rated at 1.00kW when connected toa 1.20 x 10^2 V source. (a) what current does the waffle ironcarry? (b) what is the resistance? I am stuck on the equations that I would have to use for thisproblem. I know that for the current it is I=(V)(R) and for R=V/I.How do I relate these two equations to solve the problem? Suppose your waffle iron is rated at 1.00kW when connected toa 1.20 x 10^2 V source. (a) what current does the waffle ironcarry? (b) what is the resistance? I am stuck on the equations that I would have to use for thisproblem. I know that for the current it is I=(V)(R) and for R=V/I.How do I relate these two equations to solve the problem?

Explanation / Answer

The relationship between power, voltage and current is P=VI from this solve for I I= P/V convert the KW in to watt I=1000W/120V=8.33 I=8.33A To solve for Resistance, Use the hooks law R=V/I= 120v/8.33A R=14.4 I hope this will answer your questions

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