The driver of a pickup truck going 100km/h applies the breaks,giving the truck a

Question

The driver of a pickup truck going 100km/h applies the breaks,giving the truck a uniform deceleration of 6.50m/s2while it travels 20.0m. (a) What is the speed of the truck in km/hat the end of this distance? (b) how much time has elasped? Can someone show me the steps? Thanks! The driver of a pickup truck going 100km/h applies the breaks,giving the truck a uniform deceleration of 6.50m/s2while it travels 20.0m. (a) What is the speed of the truck in km/hat the end of this distance? (b) how much time has elasped? Can someone show me the steps? Thanks!

Explanation / Answer

           Given that the initial speed of the truck is U = 100 km/h =(100*5/18 ) m/s = 27.77 m/s            The deceleration of the truck is a = - 6.50 m/s2            The distance travelled by the truck is d = 20.0 m       ---------------------------------------------------------------------------------------------                   From the equation of motion             V2 -U2 = 2ad                      V = ( U2 + 2ad )1/2                          = ( 27.77 m/s2 - 2*6.50m/s2*20m)1/2                          = ----------- m/s             this is the final speed at the end of the distance d      The time taken to travell thedistance is                     V = U + at                       t= (V - U) /a                           =---------- sec                                 = ----------- m/s             this is the final speed at the end of the distance d      The time taken to travell thedistance is                     V = U + at                       t= (V - U) /a                           =---------- sec       

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