1). A person travels by car from one city to another. Shedrives from 25.9 min at
ID: 1736382 • Letter: 1
Question
1). A person travels by car from one city to another. Shedrives from 25.9 min at 89km/h, 10.4 min at 82.2 km/h, 41.9 min at40.8 km/h and spends 10.7 min along the way eating lunch and byinggas. a. determine the distance between cities along this route inunits of km. b. the average speed for the trip in km/h 1). A person travels by car from one city to another. Shedrives from 25.9 min at 89km/h, 10.4 min at 82.2 km/h, 41.9 min at40.8 km/h and spends 10.7 min along the way eating lunch and byinggas. a. determine the distance between cities along this route inunits of km. b. the average speed for the trip in km/hExplanation / Answer
Distance travel in first 25.9 min is S = velocity *time = 89 km / h * ( 25.9 / 60 ) h = 38.41 km Distance travel in next 10.4 min is S " = 82.2 km / h *( 10.4 / 60 ) h = 14.248 km Distance travel in next 41.9 min is S ' = 40.8 km / h *( 41.9 / 60 ) h = 28.492 km So, the distance between cities along this route in units ofkm = S + S " + S ' = 81.15 km (b). Average speed = total distance / total time = 81.15 km / ( 25.9+10.4+41.9+10.7 ) / 60 h = 54.76 km / hRelated Questions
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