(a) A 10 kg box is moving at a constant velocity of 6 m/s. Thecoefficent of slid
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(a) A 10 kg box is moving at a constant velocity of 6 m/s. Thecoefficent of sliding friction is .20. A constant force is beingapplied to the box. Find this force. (b) A larger (and constant) force is now applied tothe box and its kenetic energy increases by 60 joules. Thebox moves a distance of 4 meters. Find this force. Thank You! (a) A 10 kg box is moving at a constant velocity of 6 m/s. Thecoefficent of sliding friction is .20. A constant force is beingapplied to the box. Find this force. (b) A larger (and constant) force is now applied tothe box and its kenetic energy increases by 60 joules. Thebox moves a distance of 4 meters. Find this force. Thank You!Explanation / Answer
a.The force applied is the frictional force. F=fr=mg=0.2*10g=19.6N b. Initial velocity u=6m/s final velocity v The change in KE=1/2*m(v2-62)=60J 10(v2-36)=120 v2-36=12 v2=48 v=6.928m/s Hence we get by it.Related Questions
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