Secretariat ran the 1.25 mi long Kentucky Derby with timesof 25.3 s, 24.6 s, 23.
ID: 1735683 • Letter: S
Question
Secretariat ran the 1.25 mi long Kentucky Derby with timesof 25.3 s, 24.6 s, 23.8 s, 22.5 s, and 22.2 s for each of the quarter mile segments. (a) Find his average speed during each quarter-mile segment. First segment? _____ft/sSecond segment? _____ft/s Third segment? _____ft/s
Fourth segment? _____ft/s
Fifth segment? _____ft/s
(b) Assuming that Secretariat's instantaneous speed at thefinish line was the same as the average speed during the finalquarter mile, find his average acceleration for the entire race.(Hint: Recall that horses in the Derby start from rest,anduse vf = vi + at.) _____ft/s^2 (a) Find his average speed during each quarter-mile segment. First segment? _____ft/s
Second segment? _____ft/s Third segment? _____ft/s
Fourth segment? _____ft/s
Fifth segment? _____ft/s
(b) Assuming that Secretariat's instantaneous speed at thefinish line was the same as the average speed during the finalquarter mile, find his average acceleration for the entire race.(Hint: Recall that horses in the Derby start from rest,anduse vf = vi + at.) _____ft/s^2
Explanation / Answer
averagespeed during each quarter-mile segment. (.25mile=1320ft)Firstsegment? 1320/25.3= 52.17ft/s
Secondsegment? 53.66 ft/s Thirdsegment? 55.46ft/s
Fourthsegment? 58.67ft/s
Fifthsegment? 59.46ft/s
(b) Assuming that Secretariat's instantaneous speed at thefinish line was the same as the average speed during the finalquarter mile, find his average acceleration for the entire race.(Hint: Recall that horses in the Derby start from rest,anduse vf = vi + at.)
vf=59.46ft vi=0 t=25.3 +24.6 + 23.8 + 22.5 +22.2 = 118.4s
59.46 = 0 + a(118.4) >> a=.502f/s2
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