Two runners approaching each other on a straight track haveconstant speeds of 4.

Question

Two runners approaching each other on a straight track haveconstant speeds of 4.50 m/s and 3.50 m/s, respectively, when theyare 100m apart. How long will it take for the runners to meet, andwhat positions will they meet if they maintain these speeds? Can someone show me the steps and explain? Two runners approaching each other on a straight track haveconstant speeds of 4.50 m/s and 3.50 m/s, respectively, when theyare 100m apart. How long will it take for the runners to meet, andwhat positions will they meet if they maintain these speeds? Can someone show me the steps and explain?

Explanation / Answer

v1 = 4.50 m/s, v2 = 3.50 m/s, L = 100 m, every second, their distance will be reduced by 4.50 + 3.50 = 8.00m, so for 100 m, it takes 100/8.00 = 12.5 s for them to meet. The position is 4.50*12.5 = 56.25 m from the starting point of theruuner with 4.50 m/s

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.