5. In 1992, an ice palace estimated to be 4.90x10 6 kgwas built in Minnesota. De

Question

5. In 1992, an ice palace estimated to be 4.90x106kgwas built in Minnesota. Despite this sizable mass, this structurecould be moved at a constant velocity because of the small force offriction between the ice blocks of its base and the ice of the lakeupon which it was construced. Imagine moving the entire palace witha speed of 0.200m/s on this very smooth, icy surface. once thpalace is no longer being pushed, it coasts to a stop in 10.0s.what is the average force of kinetic friction acting on the palace?what is the palace's stopping distance?

Explanation / Answer

Mass (m) of the ice palace = 4.90x106kg Initial speed(u) of the palace = 0.20 m/s Final speed (v) of the palace = 0 Time (t) taken to stop = 10.0s Now formula for calculating the value of the frictional forceis            f = ma              = m(v - u)/t              = (4.90x106kg )(0 - 0.20m/s) / (10.0s)              = - 0.098*106 N Sropping distance (S) is            S= ut + (1/2)at2 Here u = 0.200m/s         t =10.0s         a = (v - u)/t            =(0 - 0.20m/s) / (10.0s)            =- 0.020 m/s2 Substitute all these values in this formula and do thecalculation work for finding the value of the distance (S)traveled, Do the calculation work. Substitute all these values in this formula and do thecalculation work for finding the value of the distance (S)traveled, Do the calculation work.

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