Suppose the opening in the tank of Figure 10 - 54 is a heighth1 above the base a

Question

Suppose the opening in the tank of Figure 10 - 54 is a heighth1 above the base and the liquid surface is aheight h2 above the base. The tank rests onlevel ground. Click here to preview your answer. 0. h'1 = 2Click here to preview your answer. (b) At what other height, h'1, can a hole beplaced so that the emerging liquid will have the same range ?Assume v2 Figure 10 - 54 (a) At what horizontal distance from the base of thetank will the fluid strike the ground? (Express your answer usingh_1 for h1 and h_2 forh2. deltax = 1

Explanation / Answer

Applying Toricelli's law                  v1 = 2gh =2g(h2-h1) Considering the jet of liquid as a horizontal projctile, Time for vertical fall, t is given by            S= h1 = 0 + 0.5g.t2             t = (2h1/g) ---------(1) Horiz range, x = v1.t =2g(h2-h1). (2h1/g)                        = 2[(h2-h1).h1] (b) From thesymmetry of the above eqn, range is the same if h1 and h2 -h1 are interchanged, So the height of the hole above the base,                      h1' =h2-h1             t = (2h1/g) ---------(1) Horiz range, x = v1.t =2g(h2-h1). (2h1/g)                        = 2[(h2-h1).h1] (b) From thesymmetry of the above eqn, range is the same if h1 and h2 -h1 are interchanged, So the height of the hole above the base,                      h1' =h2-h1

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