Suppose the net force on an object with a mass of 2 kg is given by the following
ID: 1270652 • Letter: S
Question
Suppose the net force on an object with a mass of 2 kg is given by the following mathematical formula: F(t)=(12t^2)i+(6e^-t)j where F is measured in Newtons and t is measured in seconds as usual. Assuming the object begins at rest, located at the origin, detetermine the object's:
a) acceleration
b)velocity
c)position vectors as fuctions of time t
Hint: If you don't know how to intergrate yet, you will have to figure this out by doing "antiderivatives": once you have a, guess a function v whose derivative is a.
Explanation / Answer
F = 12 t2 i + 6e-tj
a) Acceleration, a = F /m = (12 t2 i + 6e-tj ) / 2 = (6 t2 i + 3e-t j)
b) Velocity = Integral of acceleration; v = Int {(6 t2 i + 3e-tj) dt} = (2t3 i - 3e-t j)
c) position vector = Integral of velocity ; r = Int {(2t3 i - 3e-t j) dt} = (t4/2 i + 3e-t j)
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