A force F applied to an object of mass m 1 produces an acceleration of 3.10 m/s

Question

A force F applied to an object of massm1 produces an acceleration of 3.10 m/s2. The same force applied to asecond object of mass m2 produces anacceleration of 1.70 m/s2. (a) What is the value of the ratiom1/m2?
1__________

(b) If m1 and m2 arecombined, find their acceleration under the action of the forceF.
2______ m/s2 (a) What is the value of the ratiom1/m2?
1__________

(b) If m1 and m2 arecombined, find their acceleration under the action of the forceF.
2______ m/s2

Explanation / Answer

a)so we have F=ma F=m1 * 3.1 and F=m2 * 1.7, re arranging for m1 and m2, we have m1=F/3.1,m2=F/1.7 putting m1 over m2 we obtain m1/m2 = (F/3.1)/(F/1.7) = 1.7/3.1 =0.5484 b)F=ma F=(m1+m2) * a F= [(F/3.1) + (F/1.7)] * a F=F*a*[(1/3.1) + (1/1.7)] ---> Cancel out the F's 1=a*[(1/3.1) + (1/1.7)] 1=a * 0.911 a=1.098m/s2

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.