what is the solution to this question? Has someone worked it through? Question-i
ID: 1732730 • Letter: W
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what is the solution to this question? Has someone worked it through?
Question-i1 A floor system consists of a series of parallel beams, 400 mm wide and 600 mm deep, which have simply supported spans of 7.0 m. The beams are spaced 1600 mm apart. The beams are recessed at the top to accommodate precast concrete slab units 1400 mm long which are placed in position after beams are positioned. A section of the floor system is shown in Figure 1 The precast slabs only rest on the beams and are not connected to the beams. Hence, the slabs are independent of the beams and do not add to their strength. Design and detail the precast slab units. The 100 mm thickness shown in Figure 1 is to be reduced if possible. Consider bending strength only and aim for k0.2. Take fe 40 MPa, cover -20 mm and assume that the precast slabs carry only their self-weight and a live load of 10 KPa 42 slab slab 800 beam 800 10 200 10 Precast Slab Unit 100 All dimensions in nninn 500 N12 N24 Figure 1Explanation / Answer
Given: A floor consists of series of parallel beams 400 mm wide and 600 mm deep, simply supported span 7.0 m.
Beams are spaced 1600 mm apart,
Slab thickness t = 100 mm, ku = 0.2, fc= 40 MPa, cover = 20 mm and liveload = 10KPa.
Findout: Design and details of precast slab units.
Answer: For a 1 m width of slab
Overall depth of slab, b = 600 + 20 + 5 = 625 mm ( depth + cover + half of dia reinforce bar )
Self-weight of slab = 0.21 * 24 * 102 = 5.0 kN/m2
Total live load = 10 Pa
Ultimate load = (1.4G + 1.6k) (4.5) G = 10Pa , k = 0.2
= 64.44 kN
M = 64.44 * 4.5 / 8 = 36.24 kNm
Span effective depth ratio = M / bl2 and Bending reinforcement K = M / Xbd2 is calculated
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