A diverging lens has a focal length of magnitude 15.6 cm (a) Locate the images f

Question

A diverging lens has a focal length of magnitude 15.6 cm (a) Locate the images for each of the following object distances. 31.2 cm stancem 15.6 cm ocation 7.8 cm (b) Is the image for the object at distance 31.2 real or virtual? O real o virtual Is the image for the object at distance 15.6 real or virtual? real virtual Is the image for the object at distance 7.8 real or virtual? o real o virtual (c) Is the image for the object at distance 31.2 upright or inverted? O upright inverted Is the image for the object at distance 15.6 upright or inverted? O upright inverted Is the image for the object at distance 7.8 upright or inverted? upright oinverted (d) Find the magnification for the object at distance 31.2 cm. Find the magnification for the object at distance 15.6 cm Find the magnification for the object at distance 7.8 cm Need Help? ¡

Explanation / Answer

given

f = - 15.6 cm

a )

using

1/f = 1/di + 1/do

-1/15.6 = 1/31.2 + 1/do

do = - 10.4 cm

image is Virtual

magnification

M = - 10.4 / 31.2

M = - 0.333

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using d0 = 15.6 cm

1/f = 1/di + 1/do

-1/15.6 = 1/15.6 + 1/do

do = - 7.8 cm

image is Virtual

M = - 7.8 / 15.6

M = - 0.5

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using d0 = 7.8 cm

1/f = 1/di + 1/do

-1/15.6 = 1/7.8 + 1/do

do = - 5.2 cm

image is Virtual

M = - 5.2 / 7.8

M = - 0.66

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