A large asteroid of mass 60900 kg is at rest far away from any planets or stars.

Question

A large asteroid of mass 60900 kg is at rest far away from any planets or stars. A much smaller asteroid, of mass 760 kg, is in a circular orbit about the first at a distance of 311 meters as a result of their mutual gravitational attraction. What is the speed of the second asteroid? Number m/ s Now suppose that the first and second asteroids carry charges of +3.68 C and -3.68 C, respectively. How fast would the second asteroid have to be moving in order to occupy the same circular orbit as before? Number m/s

Explanation / Answer

A). Using equilibrium of forces

GMm/r^2= mv^2/r

v^2= 6.67*10^-11* 60900/311

v= 1.143*10^-4 m/s

--------

B).

Now,

mv^2/r= kq2*q1/r^2

v^2= 9*10^9*3.68*3.68/(760*311)

v= 718.1 m/s

------

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.