. -16 points SerCP11 19 P 006 My Notas Ask Your A laboratory electromagnet produ
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Question
. -16 points SerCP11 19 P 006 My Notas Ask Your A laboratory electromagnet produces a magnetic field of magnitude 1.43 T proton moves through this field with a speed of 5.64x 106 m/s. (a) Find the magnitude of the maximum magnetic force that could be exerted on the proton. (b) What is the magnitude of the maximum acceleration of the proton? m/s2 (c) Would the field exert the same magnetic force on an electron moving through the field with the same speed? (Assume that the electron is moving in the same direction as the proton.) O Yes O No Explain. This answer has not been graded yet (d) Would the electron undergo the same acceleration? O Yes O No Explain. This answer has not been graded yet. Need Help? ?liamExplanation / Answer
A).
Max magnetic force
F= qvB= 1.6*10^-19* 5.64*10^6* 1.43= 1.29*10^-12 N
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a= F/m= 1.29*10^-12/(1.67*10^-27)= 7.73*10^14 m/s^2
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Yes, in terms of magnitude the force applied by field on electron is same but in terms of direction forces are opposite in nature.
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No, as the mass of electron is too low than proton so for a constant force, acceleration of electron is too high than proton.
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Comment in case any doubt.. good luck
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