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Ok so I know how to set up the problem: I have been plugging in the correct valu

ID: 1730895 • Letter: O

Question

Ok so I know how to set up the problem:
I have been plugging in the correct values and keep getting the wrong answer. Can someone tell me how they’re entering this into their calculator bc I keep getting it wrong. ?Your answer is partially correct. Try again. charge of-7.03 ?? ís traveling at a speed of 8.95 x 106 m/s in a region of space where there is a magnetic field. The angle between the velocity of the charge and t field is 54.2. A force of magnitude6.8S × 10-3 N acts on the charge, what is the magnitude of the magnetic feld? Number Il 1.9E-4 the tolerance is +/-2% UnitsI T

Explanation / Answer

here,

charge , q = - 7.03 uC = - 7.03 * 10^-6 C

speed , v = 8.95 * 10^6 m/s

the angle between the magnetic feild and velocity , theta = 54.2 degree

let the magnitude of magnetic feild be B

force , F = q * v * B* sin(theta)

6.85 * 10^-3 = 7 * 10^-6 * 8.95 * 10^6 * B * sin(54.2)

solving for B

B = 1.35 * 10^-4 T

the magnitude of magnetic feild is 1.35 * 10^-4 T

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