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Hi, Please, can you explain step by step. Thank You Questions 18 through 23 are

ID: 1730215 • Letter: H

Question

Hi,
Please, can you explain step by step. Thank You Questions 18 through 23 are concerned with a 1.6 kg mass which slides down a long chute and goes around a circular track one loop before going up a ramp. When it leaves the ramp at E it becomes a projectile. All the surfaces are frictionless. The speed of the mass at B, the bottom of the track is 13.0 m/s. The magnitude of the centripetal acceleration at the bottom of the track is (A) 4.3 m/s2 (B) 56.3 m/s2 (C) 9.8 m/s2 (D) 15.7 m/s2 (E) 28.7 m/s2 .What force does the track exert on the mass When it is at the bottom of the track? (point B) (A) 106 N (B) 15.7 N (C) 90.1 N (D) 74.4 N (E) 62.4 N What is the speed of the mass when it reaches point A? (A) 13 m/s (B) 3.2 m/s (C) 7.17 m/s (D) 6.5 m/s (E) 10.5 m/s

Explanation / Answer

The centripetal acceleration at the point B is              aB = vB2 /R                                  = (13.0m/s)2 / (3.0m)                   = 56.3 m/s2 (b) The force exerted on the body at the point B is              F = maB = (1.6kg)(56.3m/s2) = 90.1 N

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